How do you find the derivative of ${sin}^{2} (2 x + 3)$ $sin^2 (2x+3)$ ?

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Answer 1 · 2015-11-10T09:29:27

$\frac{d}{d x} [{sin}^{2} (2 x + 3)] = 4 sin (2 x + 3) cos (2 x + 3)$ $d/dx[sin^2(2x+3)]=4sin(2x+3)cos(2x+3)$

Use the power rule, and other differentiation rules, to get

$\frac{d}{d x} [{sin}^{2} (2 x + 3)] = 2 sin (2 x + 3) \cdot cos (2 x + 3) \cdot 2$ $d/dx[sin^2(2x+3)]=2sin(2x+3)*cos(2x+3)*2$

How do you find the derivative of sin^2 (2x+3)sin2(2x+3)sin^2 (2x+3)?