How do you find the derivative of $- {sin}^{2} (x)$ $-sin^2(x)$ ?

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Answer 1 · 2015-12-04T03:47:02

$- 2 sin (x) cos (x)$ $-2sin(x)cos(x)$

$\frac{d}{d x} [- {sin}^{2} (x)] = - 2 sin (x) \frac{d}{d x} [sin (x)] = - 2 sin (x) cos (x)$ $d/dx[-sin^2(x)]=-2sin(x)d/dx[sin(x)]=-2sin(x)cos(x)$

How do you find the derivative of -sin^2(x)−sin2(x)-sin^2(x)?