How do you find the derivative of $sin^2(x)$ ?

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Answer 1 · 2016-05-24T06:20:50

$y^'=2*sin x* cos x$

$y=a*b$

$y'=a'*b+b'*a$

$y=sin^2=sin x*sin x$

$d/(d x) sin x=cos x$

$y'=cos x*sin x+cos x*sin x$

$y^'=2*sin x* cos x$

How do you find the derivative of sin^2(x)sin^2(x)?