Question

How do you find the derivative of `sin^2(x)`?

Answer 1

`y^'=2*sin x* cos x`

Explanation:

`y=a*b`

`y'=a'*b+b'*a`

`y=sin^2=sin x*sin x`

`d/(d x) sin x=cos x`

`y'=cos x*sin x+cos x*sin x`

`y^'=2*sin x* cos x`