How do you find the derivative of ${sin}^{2} (\frac{x}{6})$ $sin^2(x/6)$ ?

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How do you find the derivative of ${sin}^{2} (\frac{x}{6})$ $sin^2(x/6)$ ?

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Answer 1 · 2016-11-12T18:25:56

$\frac{1}{6} sin (\frac{x}{3})$ $1/6sin(x/3)$

Explanation:

Diffrentiate the power first, followed by trigonometry and finally the index.

$\frac{d}{d x} ({sin}^{2} (\frac{x}{6}))$ $d/dx(sin^2(x/6))$
$= [2 sin (\frac{x}{6}) cos (\frac{x}{6})] (\frac{1}{6})$ $= [2 sin (x/6) cos (x/6)] (1/6)$
$= \frac{1}{6} sin (\frac{x}{3})$ $=1/6 sin(x/3)$

since sin2x = 2 sinxcosx

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How do you find the derivative of ${sin}^{2} (\frac{x}{6})$ $sin^2(x/6)$ ?

1 Answer

Explanation:

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