How do you find the derivative of $sin (2 x + 3)$ $sin (2x+3)$ ?

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Answer 1 · 2018-08-14T22:15:52

I tried this:

I would use the Chain Rule:> deriving the argument (red) and then the sine (blue):

$\frac{d}{d x} [sin (2 x + 3)] = 2 \cdot cos (2 x + 3)$ $d/dx[sin(2x+3)]=color(red)(2)*color(blue)(cos(2x+3))$

How do you find the derivative of sin (2x+3)sin(2x+3)sin (2x+3)?