How do you find the derivative of ${sin}^{3} (2 x)$ $sin^3(2x)$ ?

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Answer 1 · 2015-10-31T12:47:26

$6 cos (2 x) {sin}^{2} (2 x)$ $6cos(2x)sin^2(2x)$

By using the power rule, together with other rules of differentiation, we get

$\frac{d}{d x} {sin}^{3} (2 x) = 3 {sin}^{2} (2 x) \cdot cos (2 x) \cdot 2$ $d/dxsin^3(2x)=3sin^2(2x)*cos(2x)*2$

How do you find the derivative of sin^3(2x)sin3(2x)sin^3(2x)?