How do you find the derivative of #sqrt(1/x^3)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer José F. Feb 13, 2016 First write the function as #x^-(3/2)# As we know# (x^a")'=ax^(a-1)#: Then #x^-(3/2)'=-3/2x^(-5/2)# or #-3/(2sqrt(x^5))# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1229 views around the world You can reuse this answer Creative Commons License