Question

How do you find the derivative of `sqrt (x^2 +1)`?

Answer 1

`x/sqrt(x^2 + 1)`

Explanation:

`f(x) = sqrt(x^2 + 1)`
`f(x) = (x^2 + 1)^(1/2)`

`f'(x) = 1/2(x^2 + 1)^(-1/2) . (2x + 0)`
`f'(x) = (2x)/(2 sqrt(x^2 + 1))`

`f'(x) = x/sqrt(x^2 + 1)`