How do you find the derivative of the function $f (t) = 5 t - 9 t^{2}$ $f(t)=5t-9t^2$ ?

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Answer 1 · 2016-10-24T22:50:26

$f'(t) = 5 - 18t$

You need to learn the power rule for differentiation;
$d/dxx^n = nx^(n-1)$

Hence,
$f'(t) = d/dt(5t-9t^2)$
$:. f'(t) = 5d/dt(t^1) - 9d/dt(t^2)$
$:. f'(t) = 5(1)t^0 - 9(2t^1)$
$:. f'(t) = 5 - 18t$

How do you find the derivative of the function f(t)=5t-9t^2f(t)=5t−9t2f(t)=5t-9t^2?