How do you find the derivative of the function $f(x)=1.5x^2-x+3.7$ ?

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Answer 1 · 2016-12-27T09:25:00

$f'(x)=3x-1$

the rule for polynomials for differentiation is;

$y=ax^n=>f'(x)=anx^(n-1)$

$f(x)=1.5x^2-x+3.7$

$f'(x)=2xx1.5x^(2-1)-1xxx^(1-1)+0$

A constant differentiated gives $0$

$:.f'(x)=3x-1$

How do you find the derivative of the function f(x)=1.5x^2-x+3.7f(x)=1.5x^2-x+3.7?