How do you find the derivative of the function $f(x)=x^3-3x+5$ ?

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Answer 1 · 2016-12-07T10:26:42

The answer is $f'(x)=3x^2-3$

We use $(x^n)'=nx^(n-1)$

$f(x)=x^3-3x+5$

$(x^3)'=3x^2$

$(3x)'=3$

$(5)'=0$

so,

$f'(x)=3x^2-3$

How do you find the derivative of the function f(x)=x^3-3x+5f(x)=x^3-3x+5?