How do you find the derivative of the function #y=sin(tan(4x))#? Calculus Basic Differentiation Rules Chain Rule 1 Answer GiĆ³ Feb 24, 2015 I would use the Chain Rule deriving first the #sin# as it is then multiply by the derivative of #tan# as it is and finally multiply by the derivative of #4x#, giving: #y'=cos(tan(4x))*1/cos^2(4x)*4=# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 2236 views around the world You can reuse this answer Creative Commons License