How do you find the derivative of #u=(6-2x^2)^3#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Monzur R. Dec 29, 2016 #u'=-12x(6-2x^2)^2# Explanation: If #u=[f(x)]^n# Then #u'=n[f(x)]^(n-1)f'(x)# #u=(6-2x^2)^3# #u'=3(6-2x^2)^2-4x=-12x(6-2x^2)^2# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1014 views around the world You can reuse this answer Creative Commons License