Question

How do you find the derivative of `(x^2)(x^3+4)`?

Answer 1

`y'=5x^4+8x`

Explanation:

`y=(x^2)(x^3+4)`

The product rule is:

#d((u.v))/(dx)=u.d(v)/dx+v.du/dx#

`=x^2(3x^2)+(x^3+4)2x`

`=5x^4+8x`

Or you could multiply out the brackets:

let `y=x^5+4x^2`

`y'=5x^4+8x`