How do you find the derivative of xsqrt(2x - 3)x2x3?

1 Answer
Apr 1, 2016

f'(x)= (3(x-1))/sqrt(2x-3)f'(x)=3(x1)2x3

Explanation:

Using product rule f=uv => f'=u'v+uv'f=uvf'=u'v+uv', we have:

f'(x)= (xsqrt(2x-3))'=1*sqrt(2x-3)+x*1/(2sqrt(2x-3))*2f'(x)=(x2x3)'=12x3+x122x32

f'(x)= sqrt(2x-3)+x/sqrt(2x-3)

f'(x)= (3x-3)/sqrt(2x-3)

f'(x)= (3(x-1))/sqrt(2x-3)