Question

How do you find the derivative of `y=2/(3x^2)`?

Answer 1

`dy/dx=-4/(3x^3)`

Explanation:

`y = 2/(3x^2) = 2/3x^-2`

Applying the power rule:

`dy/dx= 2/3*(-2)x^-3`

`=-4/(3x^3)`