Question

How do you find the derivative of `y=2xe^x-2e^x`?

Answer 1

I found: `y'=2xe^x`

Explanation:

We can use the Product Rule to tackle `2xe^x` and remember that the derivative of `e^x` is `e^x` itself.
We get:
`y'=cancel(2e^x)+2xe^xcancel(-2e^x)=2xe^x`

Answer 2

`(d y)/(d x)=2e^x-2e^x l n(e)+2xe^x l n(e)`

Explanation:

`(d y)/(d x)=2 x e^x-2 e^x=?`

`(d y)/(d x)=2*e^x+2x*e^x*l n(e)-2e^x*l n(e)`

`(d y)/(d x)=2e^x-2e^x l n(e)+2xe^x l n(e)`