How do you find the derivative of $y=5/(2x^2)$ ?

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Answer 1 · 2017-12-14T06:49:54

$(dy)/(dx) = -5/(x^3)$

We must use the pwer rule:

$d/(dx) alphax^n = alphanx^(n-1)$

So we can write $5/(2x^2)$ as $5/2 x^-2$

Now applying the rule:

$=> (dy)/(dx) = -2* 5/2 x^(-2-1)$

$=> -5x^-3$

$=> -5/(x^3)$

How do you find the derivative of y=5/(2x^2)y=5/(2x^2)?