Question

How do you find the derivative of `y=ln(x+3)ln(x-1)`?

Answer 1

`d/(dx)(ln(x+3)ln(x+1)) = ln(x+1)/(x+3)+ln(x+3)/(x+1)`

Explanation:

We can use the product rule:

`d/(dx)( f(x)*g(x)) = f'(x) g(x) +f(x) g'(x)`

So:

`d/(dx)(ln(x+3)ln(x+1)) = ln(x+1)/(x+3)+ln(x+3)/(x+1)`