Question

How do you find the derivative of `y=(lnx)^n`?

Answer 1

`dy/dx =(n (ln x)^(n-1))/x`

Explanation:

Using the chain rule:

`dy/dx = d/dx (lnx)^n = n (ln x)^(n-1) d/dx (lnx) = (n (ln x)^(n-1))/x`