Question

How do you find the derivative of `y=pi/2sintheta-costheta`?

Answer 1

`dy/dx=pi/2costheta+sintheta`

Explanation:

`"note that " pi/2" is a constant"`

`"using "color(blue)"standard derivatives"`

`• d/dx(sinx)=cosx" and " d/dx(cosx)=-sinx`

`rArrdy/dx=pi/2cosx+sinx`