How do you find the derivative of #y = sin(tan 2x)#?
1 Answer
Nov 13, 2015
Explanation:
You must use the chain rule: this means that
In your case, we have:
#f(x)=sin(x)# , and thus#f'(x)=cos(x)# ;#g(x)=tan(x)# , and thus#g'(x)=1/cos^2(x)# ;#h(x)=2x# , and thus#h'(x)=2# .
Plugging these functions into the original formula gives:
#f'(g(h(x))) = cos(tan(2x))# #g'(h(x)) = 1/(cos^2(2x))# #h'(x) = 2#
Multiplying the three, you get
