How do you find the derivative of $y=sqrtx/x$ ?

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Answer 1 · 2017-01-03T02:19:37

$dy/dx=-1/2x^(-3/2)$

Using the power rule:

$dy/dx = d/dxsqrt(x)/x$

$=d/dxx^(1/2)/x^1$

$=d/dxx^(1/2-1)$

$=d/dxx^(-1/2)$

$=-1/2x^(-1/2-1)$

$=-1/2x^(-3/2)$

How do you find the derivative of y=sqrtx/xy=sqrtx/x?