Question

How do you find the derivative of `y=tanh(6+e^(6x))`?

Answer 1

Simple application of the chain rule.

Explanation:

`d/(du)(tanh(u)) = sech^2(u)`

`(dy)/(dx) = (dy)/(du)*(du)/(dx)`

So `sech^2(6+e^(6x))*d/(dx)(6+e^(6x))`

`(dy)/(dx) = 6*e^(6x)*sech^2(6+e^(6x))`