How do you find the derivatives of #y=e^(e^x)# by logarithmic differentiation?
2 Answers
Explanation:
Using logarithmic differentiation, log both sides of your equation:
Simplify using the logarithmic definition
Differentiate:
Simplify:
Substitute
Use the exponent rule
# dy/dx = e^(x+e^x) #
Explanation:
The process of logarithmic differentiation is simply that of taking logarithms of both sides prior to (implicitly) differentiating:
We have:
# y = e^(e^x) #
Taking logs we have:
# \ \ \ \ \ ln y = ln e^(e^x) #
# :. ln y = e^x ln e #
# :. ln y = e^x #
Differentiate (implicitly) wrt
# \ \ 1/y dy/dx = e^x #
# :. dy/dx = y e^x #
# :. dy/dx = e^(e^x) e^x #
# :. dy/dx = e^(x+e^x) #