Question

How do you find the derivatives of `y=lnabs(3x+4)`?

Answer 1

`3/(3x+4)`

Explanation:

`d/dx[ln(abs(3x+4))]`
=`1/abs(3x+4)*d/dx[abs(3x+4)]`
=`[(3x+4)/abs(3x+4)*d/dx[3x+4]]/abs(3x+4)`
=`[3*d/dx[x]+d/dx[4]]/(3x+4)`
=`[3*1+0}/(3x+4)`
=`3/(3x+4)`