How do you find the determinant of #((3, 0, -1), (4, 6, 2), (8, -2, 3))#? Precalculus Matrix Algebra Determinant of a Square Matrix 1 Answer Bdub Mar 11, 2016 #det=122# Explanation: #D=3|(6,2),(-2,3)|-0|(4,2),(8,3)|+(-1)|(4,6),(8,-2)|# #=3(18-(-4))-0 -1(-8-48)->#Use Cramer's Rule #|(r,s),(t,u)|=ru-st# #=3(22)-1(-56)# #=66+56# #det=122# Answer link Related questions What is the determinant of an inverse matrix? What is the determinant of a matrix used for? What is the determinant of a matrix to a power? What is meant by the determinant of a matrix? How do I find the determinant of a #2xx2# matrix? How do I find the determinant of a #3xx3# matrix? How do I find the determinant of of a #4xx4# matrix? How do I find the determinant of of a #5xx5# matrix? Does every matrix have a determinant? What is the cofactor expansion method to finding the determinant? See all questions in Determinant of a Square Matrix Impact of this question 1300 views around the world You can reuse this answer Creative Commons License