How do you find the domain and inverse of #f(x)=ln(3+ln(x))#? Precalculus Exponential and Logistic Functions Exponential and Logistic Graphs 1 Answer A. S. Adikesavan Jul 2, 2016 #x>e^(-3)>0.0497871#, nearly.. #x=0.0497871 (e^(e^f))#, nearly Explanation: For f to be real, #3+ln x>0#. So,# ln x>-3#. And so, #x>e^(-3) >0.0497871#, nearly. Inversion: #e^f=3+ln x.# # So, ln x = e^f-3. # And so, #x=e^(e^f-3)=e^(-3)e^(e^f)= 0.0497871 e^(e^f)# Answer link Related questions What is an exponential function? How do I find the exponential function of the form #f(x)=ab^x# for which #f(-1)=10# and #f(0)=5#? How do I find an exponential function that passes through two given points? What is the range of a logistic function? What is the general form of a logistic function? What is a logistic function? How do I find a logistic function from its graph? How does an exponential function differ from a power function? How does exponential growth differ from logistic growth? How do you find the exponential function, #n(t)=n_oe^(kt)# that satisfies the conditions... See all questions in Exponential and Logistic Graphs Impact of this question 2875 views around the world You can reuse this answer Creative Commons License