How do you find the domain and range for $y = -.566021616 (x - 6) ^2 + 3.7$ ?

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Answer 1 · 2015-09-02T20:19:32

See below.

$y = -0.566021616(x-6)^6 +3.7$

$x$ can take any value, so the domain is all real numbers.

When $x=6$ , $(x-6)^6=0$ , and $y = 3.7$ .

When $x ≠ 6$ , $(x-6)^6$ is a positive number, and $-0.566021616(x-6)^6$ is a negative number.

So $3.7$ is the maximum value of $y = -0.566021616(x-6)^6 +3.7$ .

The range is all real numbers less than or equal to $3.7$ .

How do you find the domain and range for y = -.566021616 (x - 6) ^2 + 3.7y = -.566021616 (x - 6) ^2 + 3.7?