How do you find the domain and range of $\frac{1}{\sqrt{8 - t}}$ $1/sqrt(8-t)$ ?

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Answer 1 · 2017-12-01T00:59:42

Domain: All $x$ $x$ values $< 8$ $< 8$ ; $\quad[\infty,8)$

Range: All $y$ values $>0$ ; $\quad(0,\infty]$

The domain is simply the values $x$ , or in this case $t$ , can have that will make the function defined.

For the above function, dividing by $0$ will be undefined, so $t\ne 8$ .

We can express that in interval notation as $[\infty,8)$ , which means the domain is all values of $t$ less than $8$ .

As for the range, we can plot the graph and find it from that.

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We can see the graph starts just above $0$ , and continues toward $\infty$ upward.

So we can express the range as $(0,\infty]$ , meaning all $y>0$ .

How do you find the domain and range of 1/sqrt(8-t)1√8−t1/sqrt(8-t)?