How do you find the domain and range of f(x)= -sqrt(x-3)f(x)=x3?

1 Answer
Sep 16, 2015

Domain { x in RR, x>= 3}
{y inRR, y<= 0}

Explanation:

For a function from real to real x-3 should be >=0, hence domain is { x in RR, x>= 3}.

For range solve y= -sqrt(x-3) for x, and to note that y would have to be all negative real numbers.
x= y^2 +3, hence y<=0 Range would be {y inRR, y<= 0}