How do you find the domain and range of $f (x) = x^{2} - 12 x + 36$ $f(x)=x^2-12x+36$ ?

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Answer 1 · 2015-08-19T05:35:32

Find domain and range of $f (x) = x^{2} - 12 x + 36$ $f(x) = x^2 - 12x + 36$

$f (x) = {(x - 6)}^{2}$ $f(x) = ( x - 6)^2$

The parabola opens upward. There is a Min at vertex $(6, 0)$ $(6, 0)$ .

There is also double root at $x = 6$ $x = 6$

Domain of $x$ $x$ : $(- \infty, + \infty)$ $(-oo, + oo)$

Range of $y$ $y$ : $(- \infty, + \infty)$ $(-oo, + oo)$

graph{(x - 6)^2 [-10, 10, -5, 5]}

How do you find the domain and range of f(x)=x2−12x+36f(x)=x^2-12x+36?