Question

How do you find the domain and range of `f(x)=x^2-12x+36`?

Answer 1

Find domain and range of `f(x) = x^2 - 12x + 36`

Explanation:

`f(x) = ( x - 6)^2`

The parabola opens upward. There is a Min at vertex `(6, 0)`.

There is also double root at `x = 6`

Domain of `x`: `(-oo, + oo)`

Range of `y`: `(-oo, + oo)`

graph{(x - 6)^2 [-10, 10, -5, 5]}