How do you find the domain and range of #h(x)=-sqrt(x+3)#?
1 Answer
Jan 22, 2018
Explanation:
#x+3>=0#
#rArrx>=-3#
#rArr"domain is "x inRR,x>=-3#
#rArr[-3,+oo)larrcolor(blue)"in interval notation"#
#sqrt(x+3)" has a range "[0,+oo)#
#"but "-sqrt(x+3)" is "sqrt(x+3)" reflected in the x-axis"#
#rArr"range is "[0,-oo)#
graph{-sqrt(x+3) [-10, 10, -5, 5]}
