How do you find the domain and range of y= 5sqrt((-x+3)^4)y=5(x+3)4?

1 Answer
Nov 4, 2017

Donain: (-oo,+oo)(,+) Range: [0, +oo)[0,+)

Explanation:

y= 5sqrt((-x+3)^4) y=5(x+3)4

= 5xx (-x+3)^(4/2) = 5(-x+3)^2=5×(x+3)42=5(x+3)2

yy is defined forall x in RR

Hence, the domain of y is: (-oo,+oo)

y_min = y(3) = 0

y has no finite uper bound.

Hence, the range of y is: [0, +oo)

As can be deduced from the graph of y below.

graph{5sqrt((-x+3)^4) [-2.27, 7.593, -0.676, 4.254]}