How do you find the domain and range of #y = log_2(x - 3)#?

1 Answer
Jun 21, 2015

The argument of a log-function must be positive.

Explanation:

This means #x-3>0->x>3#

If #x# gets closer to #3#, the log will get more and more negative

Or, in the "language""
#lim_(x->3) log_2 (x-3)= -oo#

The other way, #x# getting larger, will get the function larger:
#lim_(x-> oo) log_2 (x-3) = oo#