How do you find the domain and range of #y=sqrt(3-x)#? Precalculus Functions Defined and Notation Domain 1 Answer A. S. Adikesavan Jan 29, 2017 Domain : #x in (-oo, 3]# Range : #y in [0, oo)# See the illustrative semi-parabola graph. Explanation: #y=sqrt(x-3)>=0# For y to be real, #x<=3# graph{sqrt(3-x) [-10, 10, -5, 5]} Answer link Related questions What is the domain of a function? What are common mistakes students make when working with domain? How does the domain of a function relate to its x-values? What is the domain of a linear function? What is the domain of a quadratic function? What is the domain of a function like #f(x) = 5x^2#? What is the domain of #f(x) = {(1, 2), (3, 4), (5, 6), (7, 8), (9, 10), (10, 10)}#? What is the domain of #f(x) = x#? How do I find the domain of the function #f(x) = 2x#? How do I find the domain of the function #f(x)=5x^2+2x-1#? See all questions in Domain Impact of this question 15695 views around the world You can reuse this answer Creative Commons License