How do you find the domain for $g(x)=sqrt(40-8x)$ ?

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Answer 1 · 2015-04-22T11:55:27

Assuming we are restricted to Real values for
$g(x) = sqrt(40-8x)$
then
$g(x)$ is defined for all Real values of $x$ for which $(40-8x) >= 0$

That is for all Real values of $x<=5$

So the Domain of $g(x)$ is $(-oo,+5]$

How do you find the domain for g(x)=sqrt(40-8x)g(x)=sqrt(40-8x)?