How do you find the domain for $g (x) = \sqrt{40 - 8 x}$ $g(x)=sqrt(40-8x)$ ?

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How do you find the domain for $g (x) = \sqrt{40 - 8 x}$ $g(x)=sqrt(40-8x)$ ?

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Answer 1 · 2015-04-22T11:55:27

Assuming we are restricted to Real values for
$g (x) = \sqrt{40 - 8 x}$ $g(x) = sqrt(40-8x)$
then
$g (x)$ $g(x)$ is defined for all Real values of $x$ $x$ for which $(40 - 8 x) \geq 0$ $(40-8x) >= 0$

That is for all Real values of $x \leq 5$ $x<=5$

So the Domain of $g (x)$ $g(x)$ is $(- \infty, + 5]$ $(-oo,+5]$

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How do you find the domain for $g (x) = \sqrt{40 - 8 x}$ $g(x)=sqrt(40-8x)$ ?

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How do you find the domain for g(x)=sqrt(40-8x)g(x)=√40−8xg(x)=sqrt(40-8x)?

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How do you find the domain for $g (x) = \sqrt{40 - 8 x}$ $g(x)=sqrt(40-8x)$ ?