How do you find the domain of #f(x) = 2 / (1 - x²)#?

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Answer 1 · 2017-03-12T13:38:10

The domain of #f(x)# is #D_f(x)=RR-{-1,1}#

We need

#a^2-b^2=(a+b)(a-b)#

We cannot divide by #0#

The denominator must be different to #0#

#1-x^2=(1+x)(1-x)#

Therefore,

#x!=-1# and #x!=1#

The domain of #f(x)# is #D_f(x)=RR-{-1,1}#