How do you find the domain of #f(x) = ( 9x+8)/(-9-8x)#?

1 Answer
May 13, 2015

Start by finding the 'forbidden' values of #x#

The denominator of a fraction may not be zero, so let's see when it is:
#-9-8x=0->-9=8x->x=-9/8#
Answer : #x!=-9/8#
This forms a vertical asymptote:
graph{(9x+8)/(-9-8x) [-10, 10, -5, 5]}

Extra : as you can see, there is also a horizontal asymptote at

#y=-9/8#. This has to do with the range of this function