Question

How do you find the domain of `f(x)=Ln(3x+2)`?

Answer 1

The argument of the `ln` function must be `>0`

Explanation:

`->3x+2>0` subtract `2`:
`->3x> -2` divide by `3`:
`->x> -2/3`
On the other side, there is no maximun for `x`, so:
`-2/3 < x < +oo` or `(-2/3,+oo)`

graph{ln(3x+2) [-5.37, 19.94, -6.49, 6.17]}