Question

How do you find the domain of `log(3x^2-4x+5)`?

Answer 1

The domain is `RR`

Explanation:

It must be:

`3x^2-4x+5>0`

let's find the zeroes of the trynomial:

`x=(2+-sqrt(4-15))/3`

Since the expression under square root is negative,
the disequation
`3x^2-4x+5>0`
is verified for all x in `RR`