How do you find the domain of #n(t)=(6t+5)/(3t+8)#?

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Answer 1 · 2018-06-07T19:25:45

#x inRR, x!=-8/3#

The only time #n(t)# will be undefined is when our denominator is equal to zero, as we know that we cannot divide by zero.

Let's just set the denominator equal to zero. We have

#3t+8=0#

Subtracting #8# from both sides, we get

#3t=-8#

Dividing both sides by #3#, we get

#t=-8/3#

This is the only value that #n(t)# is undefined, thus or domain is

#x inRR, x!=-8/3#

Hope this helps!