How do you find the domain of $\frac{\sqrt{x + 3}}{(x + 8) (x - 2)}$ $sqrt(x+3)/((x+8)(x-2))$ ?

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Answer 1 · 2017-02-13T07:16:02

The domain is $x \in [- 3, 2 [\cup] 2, + \infty [$ $x in [-3,2[uu]2,+oo[$

What's under the square root sign is $\geq 0$ $>=0$ and we cannot divide by $0$ $0$

Therefore,

$x + 3 \geq 0$ $x+3>=0$ , $\Rightarrow$ $=>$ , $x \geq - 3$ $x>=-3$

and $x \neq - 8$ $x!=-8$

and $x \neq 2$ $x!=2$

Therefore,

the domain is $x \in [- 3, 2 [\cup] 2, + \infty [$ $x in [-3,2[uu]2,+oo[$

How do you find the domain of √x+3(x+8)(x−2)sqrt(x+3)/((x+8)(x-2))?