How do you find the domain of #sqrt(x+3)/((x+8)(x-2))#?

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Answer 1 · 2017-02-13T07:16:02

The domain is #x in [-3,2[uu]2,+oo[#

What's under the square root sign is #>=0# and we cannot divide by #0#

Therefore,

#x+3>=0#, #=>#, #x>=-3#

and #x!=-8#

and #x!=2#

Therefore,

the domain is #x in [-3,2[uu]2,+oo[#