How do you find the domain of the function $\frac{4}{x^{2} - 4}$ $4/ (x^2-4)$ ?

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Answer 1 · 2018-04-13T13:41:46

the domain is all real x except when $x = \pm 2$ $x=+-2$

For the domain, look at the denominator. For fractions, the denominator cannot equal to zero as this is considered undefined

ie $x^{2} - 4 \neq 0$ $x^2-4 !=0$

SO to find where it equal to zero, you say

$x^{2} - 4 = 0$ $x^2-4=0$

$x = \pm 2$ $x=+-2$

Therefore, the domain is all real x except when $x = \pm 2$ $x=+-2$

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