How do you find the domain of the function #F(x) = (x^2+3x+4)/(x^2+1)^(1/2)#?
1 Answer
May 16, 2018
Explanation:
#"the denominator of "f(x)" cannot be zero as this"#
#"would make "f(x)" undefined"#
#"note that "sqrt(x^2+1)>0" for all real values of x"#
#"thus there are no values of x which make the denominator"#
#"equal to zero"#
#"domain is "x inRR#
graph{(x^2+3x+4)/(sqrt(x^2+1)) [-10, 10, -5, 5]}
