How do you find the domain of the function: $g (x) = \frac{x + 5}{x^{2} - 16}$ $g(x)=(x+5)/(x^2-16)$ ?

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How do you find the domain of the function: $g (x) = \frac{x + 5}{x^{2} - 16}$ $g(x)=(x+5)/(x^2-16)$ ?

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Answer 1 · 2015-04-08T20:22:16

Set the denominator of your function different from zero. This is because you want to avoid a division by zero:
$x^{2} - 16 \neq 0$ $x^2-16!=0$
So then: $x \neq \pm 4$ $x!=+-4$
Your domain is then all the real number except $4$ $4$ and $- 4$ $-4$ .

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How do you find the domain of the function: $g (x) = \frac{x + 5}{x^{2} - 16}$ $g(x)=(x+5)/(x^2-16)$ ?

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How do you find the domain of the function: $g (x) = \frac{x + 5}{x^{2} - 16}$ $g(x)=(x+5)/(x^2-16)$ ?