How do you find the domain, VA, HA, Zeros and intercepts of y=(x^2-16)/(x^2-4)?
1 Answer
Explanation:
The denominator of y cannot be zero as this would make y undefined. Equating the denominator to zero and solving gives the values that x cannot be and if the numerator is non-zero for these values then they are vertical asymptotes.
"solve " x^2-4=0to(x-2)(x+2)=0
rArrx=+-2" are the asymptotes"
rArr"domain is " x inRR,x!=+-2
"horizontal asymptotes occur as"
lim_(xto+-oo),ytoc" (a constant )" divide terms on numerator/denominator by the highest power of x, that is
x^2
y=(x^2/x^2-16/x^2)/(x^2/x^2-4/x^2)=(1-16/x^2)/(1-4/x^2) as
xto+-oo,yto(1-0)/(1-0)
rArry=1" is the asymptote"
color(blue)"Intercepts"
x=0toy=(-16)/(-4)=4larrcolor(red)" y-intercept"
y=0tox^2-16=0to(x-4)(x+4)=0
rArrx=+-4larrcolor(red)" x-intercepts"
"which, of course are also the zeros"
graph{(x^2-16)/(x^2-4) [-10, 10, -5, 5]}