How do you find the domain, VA, HA, Zeros and intercepts of y=(x^2-16)/(x^2-4)?

1 Answer
Jul 9, 2017

"see explanation"

Explanation:

The denominator of y cannot be zero as this would make y undefined. Equating the denominator to zero and solving gives the values that x cannot be and if the numerator is non-zero for these values then they are vertical asymptotes.

"solve " x^2-4=0to(x-2)(x+2)=0

rArrx=+-2" are the asymptotes"

rArr"domain is " x inRR,x!=+-2

"horizontal asymptotes occur as"

lim_(xto+-oo),ytoc" (a constant )"

divide terms on numerator/denominator by the highest power of x, that is x^2

y=(x^2/x^2-16/x^2)/(x^2/x^2-4/x^2)=(1-16/x^2)/(1-4/x^2)

as xto+-oo,yto(1-0)/(1-0)

rArry=1" is the asymptote"

color(blue)"Intercepts"

x=0toy=(-16)/(-4)=4larrcolor(red)" y-intercept"

y=0tox^2-16=0to(x-4)(x+4)=0

rArrx=+-4larrcolor(red)" x-intercepts"

"which, of course are also the zeros"
graph{(x^2-16)/(x^2-4) [-10, 10, -5, 5]}