Question

How do you find the equation of the line through point (-3,5) (2,1)?

Answer 1

The equation of line is `4x+5y=13`

Explanation:

The equation of line passing through `(-3,5) and (2,1)` is `y-y_1=m(x-x_1) or y-5= m(x-(-3)) or y-5= m(x+3)`

The slope of the line is `m=(y_2-y_1)/(x_2-x_1)= (1-5)/(2+3)= -4/5`
Therefore , the equation of line is `y-5= -4/5(x+3) or 5y-25 =-4x -12 or 4x+5y=13`[Ans]