How do you find the equation of the plane in xyz-space through the point #p=(4, 5, 4)# and perpendicular to the vector #n=(-5, -3, -4)#?
2 Answers
Feb 19, 2015
Hello,
If the repair is orthonormal, then the plane has
Because the plane contains
So you find
Another one, easier, is
Feb 19, 2015
The answer is:
Given a poiint
So: