How do you find the equation of the tangent line to the curve #y=root4x# at (1,1)?

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Answer 1 · 2018-04-05T00:02:49

#dy/dx=1/(4x^(3/4))#

We have:

#y=x^(1/4)#

We use the power rule:

#x^n=nx^(n-1)# if #n# is a constant.

#=>dy/dx=1/4*x^(1/4-1)#

#=>dy/dx=x^(-3/4)*1/4#

#=>dy/dx=1/x^(3/4)*1/4#

#=>dy/dx=1/(4x^(3/4))#